PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!Use technology or a z-distribution table to find the indicated area.Suppose the distances from the center of a target that arrows strikes are normally distributed with a mean of 20 cm and a standard deviation of 6.4 cm.Approximately 25% of the arrows are further than what distance from the center?

Answer:  b) 15.7Step-by-step explanation:Look at the z-table (below) to find 0.2500  Notice that the value is not on the table but is between 0.2486 and 0.2517 which are located on the z-table at 0.67 and 0.68 The given value is closer to 0.2486 so use 0.67 as the z-score.Now, let's find the x-value using the formula: [tex]z=\dfrac{x-\mu}{\sigma}[/tex][tex]-0.67=\dfrac{x-20}{6.4}\\\\\\\text{Multiply both sides by 6.4:}\\-4.288=x-20\\\\\\\text{Add 20 to both sides:}\\\large\boxed{15.712} = x[/tex]